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Is the circle x ^(2) +y ^(2) = r ^(2) sy...

Is the circle `x ^(2) +y ^(2) = r ^(2)` symmetrical about the line `y=x` ?

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To determine if the circle given by the equation \( x^2 + y^2 = r^2 \) is symmetric about the line \( y = x \), we can follow these steps: ### Step 1: Understand the symmetry condition A curve is symmetric about the line \( y = x \) if swapping \( x \) and \( y \) in its equation results in the same equation. ### Step 2: Write down the original equation The equation of the circle is: \[ x^2 + y^2 = r^2 \] ### Step 3: Swap \( x \) and \( y \) To check for symmetry about the line \( y = x \), we replace \( x \) with \( y \) and \( y \) with \( x \): \[ y^2 + x^2 = r^2 \] ### Step 4: Simplify the swapped equation The equation after swapping becomes: \[ x^2 + y^2 = r^2 \] This is the same as the original equation. ### Step 5: Conclusion Since the equation remains unchanged after swapping \( x \) and \( y \), we conclude that the circle \( x^2 + y^2 = r^2 \) is symmetric about the line \( y = x \). Thus, the answer is **Yes**. ---
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