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The sum of squares of intercepts on the ...

The sum of squares of intercepts on the axes cut off by the tangents to the curve `x^(2//3)+y^(2//3)=a^(2//3) (a gt 0)` at `((a)/(8), (a)/(8))` is 2. Thus a has the value:

A

1

B

2

C

4

D

8

Text Solution

Verified by Experts

The correct Answer is:
C
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