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A point equidistant from the lines 4x+3y...

A point equidistant from the lines `4x+3y+10=0, 5x-12y+26=0 and 7x+24y-50=0` is :

A

(1, -1)

B

(1, 1)

C

(0, 0)

D

(0, 1)

Text Solution

Verified by Experts

The correct Answer is:
C
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