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If one end of the diameter of the circle...

If one end of the diameter of the circle `x^2 + y^2 - 8x - 4y + c = 0` is (-3, 2), then the other end is :

A

(5, 3)

B

(6,2)

C

(1,-8)

D

(11,2)

Text Solution

Verified by Experts

The correct Answer is:
D
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