Home
Class 12
MATHS
If the circles x^2+y^2+2x+2ky + 6=0 and ...

If the circles `x^2+y^2+2x+2ky + 6=0` and `x^2+y^2+2ky+k=0` intersect orthogonally , then k is :

A

2 or -3/2

B

`-2` or -3/2

C

2 or 3/2

D

`-2` of 3/2

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Topper's Solved these Questions

  • CIRCLES AND SYSTEMS OF CIRCLES

    MODERN PUBLICATION|Exercise MCQs LEVEL - II|51 Videos
  • CIRCLES AND SYSTEMS OF CIRCLES

    MODERN PUBLICATION|Exercise AIEEE/JEE Examination|9 Videos
  • CARTESIAN SYSTEM OF RECTANGULAR CO-ORDINATES AND STRAIGHT LINES

    MODERN PUBLICATION|Exercise Recent Competitive Questions (Questions from Karnataka CET & COMED)|8 Videos
  • COMPLEX NUMBERS

    MODERN PUBLICATION|Exercise Questions from karnataka CET & COMED|15 Videos

Similar Questions

Explore conceptually related problems

The circles x^2+y^2-12x-12y=0 and x^2+y^2+6x+6y=0 :

If the circles x^(2)+y^(2)-2 x-2 y-7=0 and x^(2)+y^(2)+4 x+2 y+k=0 cut orthogonally, then the length of the common chord of the circles is

The circles x^2+y^2+x+y=0 and x^2+y^2+x-y=0 intersect at an angle :

Circles x^2+y^2-2x-4y=0 and x^2+y^2-8y-4=0

The value of k for which the circles x^2 - y^2 + 3x - 7y +k = 0 and x^2 + y^2 - 4x + 2y - 14 = 0 would intersect orthogonallys

The locus of the centre of circle which cuts the circles x^2 + y^2 + 4x - 6y + 9 =0 and x^2 + y^2 - 4x + 6y + 4 =0 orthogonally is

The two circles x^(2) + y^(2) - 2x + 22y + 5 = 0 and x^(2) + y^(2) + 14x + 6y + k = 0 intersect orthogonally provided k is equal to...

The circles x^2+y^2+4x+6y+3=0 and 2(x^2+y^2)+6x+4y+c=0 will cut orthogonally if c is :