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If a > 2b > 0, then the positive value o...

If a > 2b > 0, then the positive value of m for which `y=mx-bsqrt(1-m^2)` is a common tangent to `x^2+y^2=b^2` and `(x-a)^2 +y^2=b^2` is :

A

`(2b)/sqrt(a^2-4b^2)`

B

`sqrt(a^2-4b^2)/(2b)`

C

`(2b)/(a-2b)`

D

`b/(a-2b)`

Text Solution

Verified by Experts

The correct Answer is:
A
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