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If the circle x^2+y^2+2gx+2fy+c=0 bisect...

If the circle `x^2+y^2+2gx+2fy+c=0` bisects the circumference of the circle `x^2+y^2+2g'x +2f'y+c'=0` , then :

A

2g(g-g')+2f(f-f')=c'-c

B

2g'(g-g')+2f'(f-f')=c-c'

C

2g'(g-g')+2f'(f-f')=c'-c

D

2g(g-g')+2f(f-f')=c-c'

Text Solution

Verified by Experts

The correct Answer is:
B
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MODERN PUBLICATION-CIRCLES AND SYSTEMS OF CIRCLES -MCQs LEVEL - II
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