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The ellipse x^2+""4y^2=""4 is inscribed ...

The ellipse `x^2+""4y^2=""4` is inscribed in a rectangle aligned with the coordinate axes, which in turn is inscribed in another ellipse that passes through the point (4, 0). Then the equation of the ellipse is (1) `x^2+""16 y^2=""16` (2) `x^2+""12 y^2=""16` (3) `4x^2+""48 y^2=""48` (4) `4x^2+""64 y^2=""48`

A

`x^(2)+16y^(2)=16`

B

`x^(2)+12y^(2)=16`

C

`4x^(2)+48y^(2)=48`

D

`4x^(2)+64y^(2)=48`

Text Solution

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The correct Answer is:
C
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