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Mean deviation for n observations x(1), ...

Mean deviation for n observations `x_(1), x_(2),….., x_(n)` from their mean `bar(x)` is given by :

A

`underset(i - 1)overset(n) sum (x_(i) - bar(x))`

B

`(1)/(n) underset(i = 1)overset(n)sum |x_(i) - bar(x)|`

C

`underset(i = 1)overset(n)sum (x_(i) - bar(x))^(2)`

D

`(1)/(n) underset(i = 1)overset(n)sum (x_(i) - bar(x))^(2)`

Text Solution

Verified by Experts

The correct Answer is:
B
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