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Let PQR be a triangle of area Delta with...

Let `PQR` be a triangle of area `Delta` with `a=2`, `b=(7)/(2)` and `c=(5)/(2)`, where a,b and c are the lengths of the sides of the triangle opposite to the angles at P,Q and R respectively. Then `(2sinP-sin2P)/(2sinP+sin2P)` equals

A

`(3)/(4Delta)`

B

`(45)/(4Delta)`

C

`((3)/(4Delta))^(2)`

D

`((45)/(4Delta))^(2)`

Text Solution

Verified by Experts

The correct Answer is:
C
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