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ABCD is a trapezium such that AB and CD ...

ABCD is a trapezium such that AB and CD are parallel and `BC bot CD`. If `/_ADB=theta`, `BC=p` and `CD=q`, then `AB` is equal to

A

`(p^(2)+q^(2)costheta)/(pcostheta+qsintheta)`

B

`(p^(2)+q^(2))/(p^(2)costheta+q^(2)sintheta)`

C

`((p^(2)+q^(2))sintheta)/((pcostheta+qsintheta)^(2))`

D

`((p^(2)+q^(2))sintheta)/(pcostheta+qsintheta)`

Text Solution

Verified by Experts

The correct Answer is:
D
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