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If y=log(secx), then (d^(2)y)/(dx^(2)) i...

If `y=log(secx)`, then `(d^(2)y)/(dx^(2))` is :

A

`-"cosec"^(2)x`

B

`sec^(2)x`

C

`-"cosec "x-xcotx`

D

`secx tanx`.

Text Solution

Verified by Experts

The correct Answer is:
B
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