Home
Class 12
MATHS
The area of the figure bounded by y=sin ...

The area of the figure bounded by y=sin x , y cos x in the first quadrant is :

A

`2(sqrt3-1)`

B

`2(sqrt2-1)`

C

`sqrt3+1`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
D
Promotional Banner

Topper's Solved these Questions

  • AREA UNDER CURVES

    MODERN PUBLICATION|Exercise MULTIPLE CHOICE QUESTIONS (LEVEL - II)|21 Videos

  • AREA UNDER CURVES

    MODERN PUBLICATION|Exercise LATEST QUESTIONS FROM AIEEE/ JEE Examinations|10 Videos

  • APPLICATION OF DERIVATIVES

    MODERN PUBLICATION|Exercise Recent Competitive Questions (Questions from Karnataka CET & COMED)|25 Videos

  • BINOMIAL THEOREM

    MODERN PUBLICATION|Exercise RCQ.s Recent Competitive Questions (Questions from Karnataka CET & Comed|6 Videos

Similar Questions

Explore conceptually related problems

The area of the region bounded by y=|x-1| and y=1 is

Find the area of the region bounded by y^2=9x,x=2,x=4 and the X-axis in the first quadrant.

The area of the figure bounded by the curves y=cosx and y=sinx and the coordinates x=0 and x= pi//4 is

Find the area of the region bounded by x^2=4y,y=2,y=4 and the Y-axis in the first quadrant.

Area bounded by y=x^(2) and y=2x is

Area bounded by y=3x and y=x^(2) is

The area of the region bounded by the curve y=sin x between the ordinates x=0, x=pi/2 and the x-axis is :

The area of the figure bounded by the parabola (y-2)^2 =x-1 , the tangent to it at the point with ordinate 3 and the x-axis is :

the area of the region bounded by y=2x-x^(2) and x-axis is

Find the area of the region bounded by x^(2)=4y,y=2,y=4 and the y-axis in the first quadrant.