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Equation of the line passing through (1,...

Equation of the line passing through (1, 1,1) and perpendicular to 2x + 3y + z = 5 is:

A

`(x-1)/(-1) =(y-1)/1=(z-1)/1`

B

`(x-1)/1=(y-1)/3 =(z-1)/2`

C

`(x-1)/3 =(y-1)/3 =(z-1)/3`

D

`(x-1)/2 =(y-1)/3 =(z-1)/1`

Text Solution

Verified by Experts

The correct Answer is:
D
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Find the equation of the plane passing through the point A(1,2,1) and perpendicular to the line joining the points P(1,4,2) and Q(2,3,5). Also find the distance of this plane from the line (x-3)/(2)=(y-5)/(-1)=(x-7)/(-1)

Knowledge Check

  • The equation of the line passing through (1, 2) and perpendicular to x+y+7=0 is :

    A
    `y-x+1=0`
    B
    `y-x-1=0`
    C
    `y-x+2=0`
    D
    `y-x-2=0`

  • Equation of the plane passing through (1,1,1) and (1,-1,-1) and perpendicular to 2x-y+z+5=0 is

    A
    2x+5y+z-8 = 0
    B
    x+y-z-1 = 0
    C
    2x+5y+z+4 = 0
    D
    x-y+z-1 = 0

  • Equation of the line passing through (1,1,1) and parallel to the plane 2x+3y+z+5=0

    A
    `(x-1)/1 = (y-1)/2 = (z-1)/1`
    B
    `(x-1)/-1 = (y-1)/1= (z-1)/-1`
    C
    `(x-3)/3 = (y-1)/2 = (z-1)/1`
    D
    `(x-1)/2 = (y-1)/3 = (z-1)/1`

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