Home
Class 12
MATHS
A plane passes through (1, - 2, 1) and i...

A plane passes through (1, - 2, 1) and is perpendicular to the planes 2x - 2y +z = 0 and x-y + 2z = 4. The distance of the plane from the point (1, 2, 2) is:

A

0

B

1

C

`sqrt2`

D

`2sqrt2`

Text Solution

Verified by Experts

The correct Answer is:
D
Promotional Banner

Topper's Solved these Questions

  • THREE DIMENSIONAL GEOMETRY

    MODERN PUBLICATION|Exercise AIEEE/JEE Examination|16 Videos
  • THREE DIMENSIONAL GEOMETRY

    MODERN PUBLICATION|Exercise Recent Competitive Questions (RCQs)|10 Videos
  • STATISTICS

    MODERN PUBLICATION|Exercise QUESTION FROM KARNATAKA CET & COMED|3 Videos
  • TRIGONOMETRIC RATIOS, IDENTITIES AND EQUATIONS

    MODERN PUBLICATION|Exercise RECENT COMPETITIVE QUESTIONS|12 Videos

Similar Questions

Explore conceptually related problems

The plane passing through the point (a, b, c) and parallel to the plane x + y + z = 0 is:

Equation of the line passing through (1, 1,1) and perpendicular to 2x + 3y + z = 5 is:

The equation of a plane passing through the line of intersection of the planes: x + 2y + 3z = 2 and x- y + z = 3 at a distance 2/sqrt3 from the point (3,1,-1) is :

Find the distance of the plane 2x-3y+4z-6= 0 from the origin

Equation of the plane through P(1,2,3) and parallel to the plane x+2 y+5 z=0 is

The angle between the two planes 3x- 4y + 5z = 0 and 2x-y - 2z = 5 is :

The angle between the planes: 3x - 4y + 5z = 0 and 2x-y-2z = 5 is:

The planes 2x-y+4 z=5 and 5x-2.5y+10z=6 are

If the planes x + 2y + kz = 0 and 2x+y - 2z = 0 are at rt. angles, then the value of k is: