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Let the line (x-2)/3=(y-1)/(-5)=(z+2)/2 ...

Let the line `(x-2)/3=(y-1)/(-5)=(z+2)/2` lie in the plane `x+3y-alpha z+beta =0`. Then `(alpha,beta)` equals :

A

(6,-17)

B

(-6,7)

C

(5,-15)

D

(-5,5)

Text Solution

Verified by Experts

The correct Answer is:
B
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