At `60^(@)` and 1 atm, `N_(2)O_(4)` is `50%` dissociated into `NO_(2)` then `K_(p)` is

At 60^(@_C and 1 atm, N_2O_4 is 50% dissociated into NO_2 then K_p is -

At 27^(@)C and 1 atm pressure , N_(2)O_(4) is 20% dissociation into NO_(2) . What is the density of equilibrium mixture of N_(2)O_(4) and NO_(2) at 27^(@)C and 1 atm ?

At 27^(@)C and 1 atm pressure , N_(2)O_(4) is 20% dissociation into NO_(@) .What is the density of equilibrium mixture of N_(2)O_(4) and NO_(2) at 27^(@)C and 1 atm?

At 27^(@)C and 1 atm pressure , N_(2)O_(4) is 20% dissociation into NO_(@) .What is the density of equilibrium mixture of N_(2)O_(4) and NO_(2) at 27^(@)C and 1 atm?

At 27^(@)C and 1 atm pressure , N_(2)O_(4) is 20% dissociation into NO_(@) .What is the density of equilibrium mixture of N_(2)O_(4) and NO_(2) at 27^(@)C and 1 atm?

N_(2)O_(4) is 25% dissociated at 37^(@)C and 1 atm . Calculate K_(p)

At 60^(@) N_(2)O_(4) is 50% dissociated at this temperature and one atmosphere pressure the standard free energy change is

At 340 K and 1 atm pressure, N_(2)O_(4) is 66% into NO_(2) . What volume of 10 g N_(2)O_(4) occupy under these conditions?