log_(15)2+log_(-16)(16)/(165)+12log_(24)+7log_(80)(81)/(80)=1

prove that log2+16log((16)/(15))+12log((25)/(24))+7log((81)/(80))=1

log_(16)64-log_(64)16

prove that log2 + 16 log(16/15) + 12 log(25/24) + 7 log(81/80) = 1

Prove that log2+16(log16)/(15)+12(log25)/(24)+7(log81)/(80)=1

If 7"log"_(a)(16)/(15)+5"log"_(a)(25)/(24)+3"log"_(a)(81)/(80)=8 , then a=

Prove that (ii) log_(10)15(1+log_(15)30)+1/2 log_(10)16(1+log_(4)7)-log_(10)6(log_(6)3+1+log_(6)7) = 2

Prove that "log" 2 + 16 "log" (16)/(15) + 12 "log " (25)/(24) + 7 "log"(81)/(80) = 1 .

Givenlog (2)=0.3010 and log_(10)(3)=0.4771 find the value of 7log_(10)((10)/(9))-2log_(10)((25)/(24))+3log_(10)((81)/(80))