A particle moves along x-axis according to the law `x=(t^(3)-3t^(2)-9t+5)m`. Then :-

A particle moves along a line according to the law s(t)=2t^(3)-9t^(2)+12t-4 , where tge0 . Find the particle's acceleration each time the velocity is zero.

A particle moves along a line according to the law s(t)=2t^(3)-9t^(2)+12t-4 , where tge0 . At what times the particle changes direction?

A particle moves along a line according to the law s(t)=2t^(3)-9t^(2)+12t-4 , where tge0 . Find the total distance travelled by the particle in the first 4 seconds.

A particle moves along a line according to the law s=t^4-5t^2+8 . The intial velocity is

A particle moves along a straight line according to the law s=t^3-3t^2+5t . Find its velocity and acceleration at the end of 1 sec.

A particle moves according to the law x=t^(3)-6t^(2)+9t+5 . The displacement of the particle at the time when its acceleration is zero, is

A particle moves along a straight line according to the law s=t^3/3 -3t^2+9t+17 , where s is in meters and t in second. Velocity decreases when

A particle is moving along a line according to the law s=t^3-3t^2+5 . The acceleration of the particle at the instant where the velocity is zero is

A particle moves according to the law s=t^(3)-9t^(2)+24t . The distance covered by the particle before it first comes to rest is -

A particle moves along the x axis according to the law x=a cos omega t . Find the distance that the particle covers during the time interval from t=0 to t .