The density of copper is 8.95 g `cm^(-3)` .It has a face centred cubic structure .What is the radius of copper atom?
Atomic mass Cu =63.5 `gmol^(-1)N_(A)=6.02xx10^(23) mol^(-1)`

Explanation

To find the radius of a copper atom given its density and structure, we can follow these steps:

### Step 1: Identify the parameters
- Density of copper (ρ) = 8.95 g/cm³
- Atomic mass of copper (M) = 63.5 g/mol
- Avogadro's number (N_A) = 6.02 x 10²³ mol⁻¹
- For a face-centered cubic (FCC) structure, the number of atoms per unit cell (Z) = 4.

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