The conductivity of 0.20 M solution of KCl at 298 K is 0.0248 S `cm^(-1)` . Calculate its molar conductivity.

Explanation

`K(Scm^(-1))=0.025 Scm^(-1)and`
Molarity `(mol L^(-1))=0.20 M`
`" Molar conductivity "(^^_m)=(Kxx1000)/("molarity")`
`=(0.025xx1000)/(0.20)=125Scm^2//mol`