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(a)For the reaction : 2AgCl (s) + H(2)...

(a)For the reaction :
`2AgCl (s) + H_(2)(g) ` (1 atm) ` to 2 Ag(s) + 2H^(+) (0.1M) + 2Cl^(-) (0.1M) , DeltaG^(@) = -43600J` at `25^(@)`C.
Calculate the e.m.f. of the cell . [log `10^(-n) = -n`].
(b) Define fuel cell and write its two advantages.

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### Step-by-Step Solution **(a) Calculation of e.m.f. of the cell** 1. **Write the Reaction and Given Data:** The reaction is: \[ 2 \text{AgCl (s)} + \text{H}_2(g) \rightarrow 2 \text{Ag (s)} + 2 \text{H}^+(0.1 \text{ M}) + 2 \text{Cl}^-(0.1 \text{ M}) ...
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For the reaction , 2Agcl_((s)) + H_(2(g)) (1atm) rightarrow 2Ag_((s)) + 2H ^(+) (0.1M) + 2Cl^(-) (0.1M) DeltaG^(@) = -43600 J at 25^(@) C . Calculate the e.m.f. of the cell

For the reaction , 2AgCl(s)+H_(2)(g)(1" atm")to2Ag(s)+2H^(+)(0.1 M)+2Cl^(-)(0.1 M),DeltaG^(@)=-43600" J at "25^(@)C . Calculate e.m.f. of the cell.

The reaction, (1)/(2) H_(2) (g) + Ag Cl (s) = H^(+) (a.q) + Cl^(-) (a.q) + Ag (s) occurs in the galvanic cell:

DeltaG^(@) of the cell reaction AgCl(s) + 1/2H_(2) rightarrow Ag(s) + H^(+) + Cl^(-) is -21.52kJ . DeltaG^(@) of 2AgCl(s) + H_(2)(g) rightarrow + 2H^(+) + 2Cl^(-) is

DeltaG^(@) of the cell reaction AgCl(s) + 1/2H_(2) rightarrow Ag(s) + H^(+) + Cl^(-) is -21.52kJ . DeltaG^(@) of 2AgCl(s) + H_(2)(g) rightarrow + 2H^(+) + 2Cl^(-) is

Delta G^@ of the cell reaction AgCl (s) = 1/2 H_2 (g) =Ag(s) H^+ + Cl^(-) is -21 . 52 kJ . Delta G^2 of 2 AgCl (s) + H_2 (g) = 2 Ag(s) + 2 H^(+) 2 Cl^(-) is .

Calculate the emf of the following cell at 25^(@)C Ag(s) |Ag+ (10^(-3)M) | |Cu 2+ (10^(-1)M | Cu(s) :

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