(a) (i) Complete the following chemical equations :
(i)`NaOH_((aq))+Cl_(2(g)) rightarrow`
(Hot and conc.)
(ii) `Xef_(6)(s)+H_(2)O(l) rightarrow`
(b) How would you account for the following ?
(i) The value of electron gain enthalpy with negative sign for sulphur is higher than that for oxygen.
(ii) `NF_(3)` is an exothermic compound but `NCl_(3)` is endothermic compound.
(iii)`ClF_(3)` molecule has a T-shaped structure and not a trigonal planar one.

Explanation

(a)(i) `6NaOH +3Cl_(2) rightarrow 5 NaCl +NaCl O_(3)+ 3H_(2)O`
(ii)` Xe F_(6)+ H_(2)O rightarrow Xe OF_(4)+2HF`
(b) (i) Because of larger size of sulphur atom than oxygen atom.
(ii) Because bond energy of `F_(2)` is lowerthan `Cl_(2)` and N-F bond is smaller and stronger than N-Cl bond.
(iii) Because it has `dsp^(3)` hybridization.