When a coordination compound `CrCl_3`.`6H_2O` is mixed with `AgNO_3` two moles of AgCl are precipitated per mole of the compound .What is the structural formula of the coordination compound ?

Explanation

To determine the structural formula of the coordination compound \( \text{CrCl}_3 \cdot 6\text{H}_2\text{O} \) based on the information provided, we can follow these steps:

### Step 1: Analyze the given coordination compound
The coordination compound is \( \text{CrCl}_3 \cdot 6\text{H}_2\text{O} \). Here, chromium (Cr) is the central metal atom, and it is coordinated with three chloride ions (Cl\(^-\)) and six water molecules (H\(_2\)O).

### Step 2: Understand the reaction with AgNO\(_3\)
When \( \text{CrCl}_3 \cdot 6\text{H}_2\text{O} \) is mixed with \( \text{AgNO}_3 \), it precipitates two moles of AgCl per mole of the compound. This indicates that two chloride ions are released from the coordination sphere during the reaction.

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