At `300K,36g` of glucose present per litre in its solution had an osmotic pressure `4.98 ` bar. If the osmotic pressure of solution is `1.52` bar at the same temperature, what would be its concentration.

Explanation

`pi_1=4.98 "bar " ,pi_2=1.52 "bar",C_1=30/180`
Now ,according to van't haff equation `pi= CRT`
`4.98= 30/180 RT`
`1.52 = C_2RT`
Now ,dividing equation (ii) by equation (ii) by equation (i)
`(C_2xx 180)/(30)=(1.52)/(4.98)`
`C_2=(1.52xx30)/(4.98 xx 180)`
`C_2=0.0508.`