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Consider the reaction R rarr P for which...

Consider the reaction `R rarr P` for which the change in concentration of R with time is shown by the following graph:
( i) Predict the order of reaction .
( iii) What does the slope of the curve indicate ?
( b) The rate of reaction quadruples when temperature chages from 293 K of 313 K .Calculate Ea assuming that it does not chage with time `[R=8.314 JK^(-1) mol^(-1)]`

Text Solution

Verified by Experts

It is zero order reation
( ii) Slope of this curve `=-K,"where"K=([R]_0-[R])/(t)`
( b)` log""K_2/K_1=E_a/(2.303 R )((T_2-T_1)/(T_1 T_2))`
It is given that `K_2= 4K_1`
`T_1=293 K,T_2= 313 K`
` log"" (4K_1)/(K_1)=(E_a)/(2.303xx 8.314)((313-293)/(293 xx 313)) rArr 0.6021 = (20Ea)/(2.303 xx 8.314xx293xx313)`
`rArr " " Ea=(0.6021xx2.303xx8.134xx293xx313)/(20)=52863.33J mol^(-1)=52.86 kJ mol^(-1)`
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