A solution of `CuSO_(4)` is electroysed for 10 minutes with a current of 1.5 amperes. What is the mass of copper deposited at the cathode ?
(Molar mass of `Cu=63.5 g//mol)`

Explanation

Current Strength (I) =1.5A
Time (t) =10 min `=10xx60=600`s
Quantity of electrycity passed
`Ixxt`
`=(1.5A)xx(600S)`
`=900 C (AS=C)`
Copper is deposited as : `Cu^(2+)+2e^(-)toCu(s)`
2 mol of electrons of `2xx96500` C of current deposit copper = 63.56 g
900 C of current will deposit copper
`=(63.56)/(2xx96500)xx900=0.296g`.