Silver crystallises with face - centred cubic unit cells .each side of the unit cell has a length of 409 pm . What is the radius of an atom of silver ? (Assume that each face atom is touching the four corner atoms.)

Explanation

Here , side of unit cell a= 409 pm
The radius of f.c.c unit cell,
`r=(a)/(2sqrt(2))=0.3535a=0.3535xx409=144.5815`pm