Silver crystalilises in a fcc lattice. The edge length of its unit is `4.077xx10^(-8)xxcm` and its density is `10.5g cm^(-3)`. Claculate on this basis the atomic mass of silver `(N_(A)=6.02xx10^(23) "mol"^(-1))`

Explanation

`a=4.07xx10^(-8)cm, z=4["for"f.c.c.]`
`d=10.5g//cm^(3),d=(ZxxM)/(a^(3)xxNa)`
`M=(dxx(a)^(3)xxNa)/(Z)=(10.5xx(4.07xx10^(-8))^(3)xx6.022xx10^(23))/(4)`
`thereforeM=106.6g//mol`