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The conductivity of 0.20 M solution of K...

The conductivity of 0.20 M solution of KCl at 298 K is 0.0248 S `cm^(-1)` . Calculate its molar conductivity.

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Here K=`0.0248 S cm^(-1)," "` Molarity =0.20 m
Molar conductivity `^^_(m)^(c)=(Kxx100)/("Molarity")`
`" "=(0.0248xx1000)/(0.20)=(248xx1000)/(20000)=12.4 S cm^(2) "mol"^(-1)`
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