The density of lead is `11.35 g cm^(-3)` and the metal crystallizes with fee unit cell. Estimate the radius of lead atom. (At. Mass of lead `= 207 g mol^(-1) and NA = 6.02xx10^23 mol^(-1))`

Explanation

To estimate the radius of a lead atom given the density of lead and its crystallization structure, we can follow these steps:

### Step 1: Understand the given values
- Density of lead (ρ) = 11.35 g/cm³
- Atomic mass of lead (M) = 207 g/mol
- Avogadro's number (N_A) = 6.02 x 10²³ mol⁻¹
- For FCC (Face-Centered Cubic) unit cell, the number of atoms per unit cell (Z) = 4

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