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A solution is prepared by dissolving 10g...

A solution is prepared by dissolving 10g of non-volatile solute in 200g of water. It has a vapour pressure of 31.84 mm Hg at 308 K. Calculate the molar mass of the solute. (Vapour pressure of pure water at 308K =32 mm Hg)

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To find the molar mass of the solute, we need to use Raoult's law. Here is the step-by-step solution: 1. **Given Data:** - Mass of solute (\( W_s \)) = 10 g - Mass of solvent (water, \( W_w \)) = 200 g - Vapour pressure of pure water (\( P_0 \)) = 32 mm Hg - Vapour pressure of solution (\( P_s \)) = 31.84 mm Hg ...
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