A flower of tomato plant following the process of sexual reproduction produces 240 viable seeds.
Answser the following questions giving reasons :
(a) What is the minimum number of pollen grains that must have been involved in the pollination of its pistil ?
(b) What would have been the minimum number of ovules present in the ovary ?
(c) How many megaspore mother cells were involved ?
(d) what is the minimum number of microspore mother cells involved in the above case ?
(e) How many male gametes were involved in this case ?

Explanation

The Number of viable seed produces - 240 seeds, The minimum number of pollen grains that must have been involved in the pollination of its pistil are 240 because each pollen gt,ains contains two male gametes. Out of these two gametes, one fuses with polar nuclei and forms endosperm, while the other male gamete fuses with the egg cell to form the zygote that eventually give rise to seeds. In order to obtain 240 seeds, number of pollen grains needed would be 240.
(b ) The number of ovules minimally involves in this Process would be 240, as the number of viable seeds is 240. After fertilization, the ovary turns into fruit and the ovules turn into seeds. Therefore, the number of ovules is corresponding to the number of seeds formed.
( c) During the process 240 megaspore mother cells are involved as only one megaspore of the tetrad becomes functional and develops further and the rest three megaspores get degenerated.
( d) 60 microspore mother cells must have undergone reduction division prior to dehiscence of anther, as each micro spore mother cell would give rise to 4 microspores. 1 microspore mother cell would produce 4 microspores, therefore, to obtain 240 microspores, there must be 60 microspore mother cells.
(e) The number of male gametes involve in seed formation would be 240 as each male gamete will fuse with one egg nucleus to form zygote, which will further give rise to the seed.