A particle moves along the curve `y = x^2 /2.` Here x varies with time as `x = t^2 /2.` Where x and y are measured in metres and t in seconds. At `t = 2 s,` the velocity of the particle (in `ms^-1`) is

A particle moves along the positive branch of the curve y = (x^(2))/(2) where x = (t^(2))/(2),x and y are measured in metres and t in second. At t = 2s , the velocity of the particle is

A particle moves along the positive branch of the curve y = (x^(2))/(2) where x = (t^(2))/(2),x and y are measured in metres and t in second. At t = 2s , the velocity of the particle is

A particle moves on the curve y = x^(2)/4 where x=t/2. x and y are meausured in metre and t in second. At t=4s the velocity of particel is

A particle moves along the positive branch of the curve y =2x2where x =2t2,where x and y are measured in metre and t in second. At t = 2 sec, the velocityof the particle is -

A particle moves along the positive branch of the curve with x governed by where x and y are measured in meters and t in seconds. At t = 2s, the velocity of the particle is

A particle moves along positive branch of the curve, y = x/2, where x = t^3/3 , x and y are measured in meters and t in seconds, then

A particle moves along 1 ositive branch of the curve y=(x)/(2) where x=(t^(3))/(3) , x and y are measured in metres and t in seconds, then-

The position x of a particle varies with time t as x = 6 + 12t - 2 t^2 where x is in metre and in seconds. The distance travelled by the particle in first five seconds is

A particle is moving along x-y plane. Its x and y co-ordinates very with time as x=2t^2 and y=t^3 Here, x abd y are in metres and t in seconds. Find average acceleration between a time interval from t=0 to t=2 s.