Coordinates of the vertices `B` and `C` of a `triangle ABC` are `(2,0)` and `(8,0)` respectively.The vertex `A` is varying in such a way that `4tan((B)/(2))tan((C)/(2))=1` and locus of `A is "((x-5)^(2))/(25)+(y^(2))/(k^(2))=1` ,then `k=`

The coordinates of the vertices B and C of a triangle ABC are (2,0) and (8,0), respectively.Vertex A is moving in such a way that 4tan(3)/(2)tan(C)/(2)=1. Then find the locus of A

Coordinates of the vertices B and C of DeltaABC are (2, 0) and (8, 0) respectively. The vertex is hanging in such a way that 4 tan B/2.tan C/2 = 1 . Then the locus of A is (A) (x-5)^2/25 + y^2/9 = 1 (B) (x-5)^2/25 + y^2/16 = 1 (C) (c-5)^2/16 + y^2/25 = 1 (D) none of these

If the vertices A,B,C of a triangle ABC are (1,2,3),(-1,0,0) ,(0,1,2) , respectively, then find angleABC .

Base BC of triangle ABC is fixed and opposite vertex A moves in such a way that tan.(B)/(2)tan.(C)/(2) is constant. Prove that locus of vertex A is ellipse.

If the position vectors of the vertices a, B and C of a Triangle ABC be (1, 2, 3), (-1, 0, 0) and (0, 1, 2) respectively then find angleABC .

In Delta ABC, vertex B and C are fixed and vertex A is variable such that 2sin((B-C)/(2))=cos((A)/(2)) then locus of vertex A is

If A(-2,1),B(2,3) and C(-2,-4) be the vertices of a triangle ABC , show that tan B=(2)/(3)

In Delta ABC if tan((A)/(2))tan((B)/(2))+tan((B)/(2))tan((C)/(2))=(2)/(3) then a+c

In any Delta ABC, prove that :1-tan((A)/(2))tan((B)/(2))=(2c)/(a+b+c)

Show that in any triangle ABC,(a+b+c)(tan((A)/(2))+tan((B)/(2)))=2c cot((C)/(2))