Suppose the eccentricity of the ellipse `(x^(2))/(a^(2)+3)+(y^(2))/(a^(2)+4)=1` is `(1)/(sqrt(8))` .Let l be the latus rectum of the ellipse,then 4l is

If the eccentricity of the ellipse,(x^(2))/(a^(2)+1)+(y^(2))/(a^(2)+2)=1 is (1)/(sqrt(6)) then latus rectum of ellipse is

Suppose the eccentricity of the ellipse x^2/(a^2+3)+ y^2/(a^2+4)=1 is 1//sqrt8 . Let l be the latus rectum of the ellipse, then l equals

Eccentricity of the ellipse 4x^(2)+y^(2)-8x-2y+1=0

If eccentricity of the ellipse (x^(2))/(a^(2)+1)+(y^(2))/(a^(2)+2)=1 is (1)/(sqrt6) , then the ratio of the length of the latus rectum to the length of the major axis is

The eccentricity of the ellipse x^(2)+4y^(2)+8y-2x+1=0 , is

The lenth of the latus rectum of the ellipse 3x^2+y^2=12 is :

Eccentricity of the ellipse 4x^(2)+y^(2)-8x+2y+1=0 is

Find the equation of the normal to the ellipse (x^(2))/(a^(2))+(y^(2))/(b^(2))=1 at the positive end of the latus rectum.