White vitriol is `ZnSO_(4).xH_(2)O` .What is `x` ?

Calculate the percentage compostion of various elements in the following compounds: Blue vitriol (CuSO_(4). 5H_(2) O) b. Green vitriol (Fe SO_(4) . 7H_(2) O) c. White vitriol (ZnSO_(4). 5H_(2) O) d. Ethanol (C_(2) H_(5) OH) e. Mohr's salt [(NH_(4))_(2) SO_(4). FeSO_(4). 6H_(2) O]

Which of the following incorrect match ? Rinmann's green - CoO.ZnO White vitriol - \(ZnSO_{4}\).7H_(2)O Blue vitriol - \(CuSO_{4}.5H_{2}O\) Green vitriol- \(CuSO_{4} .5H_{2}\)O

The percentage weight of Zn in white vitriol [ZnSO_(4)*7H_(2)O] is approximately equal to (at. Mass of Zn =65 , S= 32, O=16 and H=1)

The sulphate of a metal A contains 20% of M. This sulphate is isomorphous with ZnSO_(4).7H_(2)O . The atomic mass of M is

The sulphate of a metal M contains 9.87% of M. The sulphate is isomorphous with ZnSO_(4).7H_(2)O . The atomic weight of M is

The sulphate of a metal M contains 9.87% of M , This sulphate is isomorphous with ZnSO_(4).7H_(2)O . The atomic weight of M is