C is the centre of the ellipse `(x^(2))/(25)+(y^(2))/(16)=1` and `S` is one of the foci.The ratio of `CS` to semi major axis is

The foci of the ellipse (x^(2))/(4) +(y^(2))/(25) = 1 are :

If C is the centre of the ellipse 9x^(2) + 16y^(2) = 144 and S is one focus. The ratio of CS to major axis, is

If C is the center of the ellipse 9x^(2)+16y^(2)=144 and S is a focus,then find the ratio of CS to the semi-major axis.

Foci of the ellipse 16x^(2)+25y^(2)=400 are

Find the maximum area of an isosceles triangle incribed in the ellipse (x^(2))/(25)+(y^(2))/(16)=1, with its vertex atone end of the major axis.

If C is centre of the ellipse x^(2)/a^(2) + y^(2)/b^(2) = 1 and the normal at an end of a latusrectum cuts the major axis in G, then CG =

Let P be a variable on the ellipse (x^(2))/(25)+ (y^(2))/(16) =1 with foci at F_(1) and F_(2)

Suppose S and S' are foci of the ellipse (x^(2))/(25)+(y^(2))/(16)=1 . If P is a variable point on the ellipse and if Delta is the area (in sq. units) of the triangle PSS' then the maximum value of Delta is double of