To divide a line segment BC internally in the ratio 3 : 5, we draw a ray BX such that `angle ` CBX is an acute angle. What will be the minimum number of points to be located at equal distances, on ray BX?

To construct a triangle similar to a given DeltaABC with its sides (3)/(7) of the corresponding sides of DeltaABC , first draw a ray BX such that angleCBX is an acute angle and X lies on the opposite side of A with respect to BC. The minimum number of points to be located at equal distances on ray BX is

To construct a triangle similar to a given Delta ABC with its sides (8)/(5) of the corresponding sides of Delta ABC draw a ray BX such that angleCBX is an acute angle and X is on the opposite side of A with respect of BC. The minimum number of points to be located at equal distances on the ray BX is

To divide a line segment AB in the ratio 4:7, a ray AX is drawn first such that angleBAX is an acute angle and then points A_(1),A_(2),A_(3),….. are located at equal distance on the ray AX and the point B is joined to

AB is a line segment of lengh 10 cm which is internally divided in the ratio 3 : 2. angle BAX is a ……….. angle.

To divide a line segment AB in the ratio 5:6, draw a ray AX such that angleBAX is an acute angle, the draw a ray BY parallel to AX and the points A_(1),A_(2),A_(3),….." and " B_(1),B_(2),B_(3),….. are located to equal distances on ray AX and BY, respectively. Then, the points joined are

Draw a line segment of 5.6cm. Divide it in the ratio 2:3.