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a)State Gauss’s law in electrostatics. S...

a)State Gauss’s law in electrostatics. Show that with help of suitable figure that outward flux due to a point charge Q, in vacuum within gaussian surface, is independent of its size and shape.
b) In the figure there are three infinite long thin sheets having surface charge density `+2sigma, -2sigma and +sigma` respectively. Give the magnitude and direction of electric field at a point to the left of sheet of charge density `+2sigma` and to the right of sheet of charge density `+sigma`

Text Solution

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(a) Statement of Gauss law
Proof of outward flux due to a point charge Q ,in vacuum within gaussian surface, is independent of its size and shape
(b) Net electric field towards left=`sigma//epsi` left
Net electric field towards right =`sigma//epsi` right
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Knowledge Check

  • Three non-conducting large parallel plates have surface charge densities sigma, -2 sigma and 4 sigma respectively as shown in the figure. The electric field at the point P is

    A
    `(sigma)/(epsilon_0)`
    B
    `(sigma)/(2 epsilon_0)`
    C
    `(3 sigma)/(2epsilon_0)`
    D
    `(3sigma)/(epsilon_0)`

  • Two infinitely long parallel sheets having surface charge densities +sigma and -sigma respectively are separated by a small distance. The electric field in the region between the plates is

    A
    `0`
    B
    `(sigma)/( 2 in_0) `
    C
    ` (sigma)/(in_0) `
    D
    ` (2sigma)/( in_0) `

  • The electric intensity at a point near a charged conductor of surface charge density sigma is

    A
    `E=sigma//in_(0)k`
    B
    `E=sigmain_(0)k`
    C
    `E=sigma//2in_(0)k`
    D
    `E=sigma^(2)`

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    The figure shows three infinite non-conducting plates of charge perpendicular to the plane of the paper with charge per unit area +sigma, +2sigma and -sigma . Find the ratio of the net electric field at that point a to that at point B.

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