Define * on `Q-{-1}` by a*b=a+b+ab then ,*on Q-{-1} is

Let * be a binary operation on Q-{-1} defined by a*b=a+b+ab for all a,b in Q-{-1}. Then,Show that * is both commutative and associative on Q-{-1} (ii) Find the identity element in Q-{-1}

Let ^(*) be a binary operation on Q-{-1} defined by a*b=a+b+ab for all a,b in Q-{-1}. Then,Show that every element of Q-{-1} is invertible.Also,find the inverse of an arbitrary element.

Let * be a binary operation defined on set Q-{1} by the rule a*b=a+b-ab .Then, the identity element for * is (a) 1 (b) (a-1)/(a) (c) (a)/(a-1) (d) 0

The identity element for the binary operation ** defined on Q ~ {0} as a**b = (ab)/2' AA a,b in Q - {0} is .........

Show that the operation ** on Q - {1} defined by a ** b = a + b - ab AA a, b inQ-{1} is commutative.

Show that the operation '**' on Q - {1} defined by a**b=a+b-ab for all a,binQ-{1} , satisfies the commutative law.

Find the idenity and inverse if any for the binary operation ** on Q-{0} defined by a**b=(ab)/4, a, b in Q-{0}

Let * be a binary operation on Q-{-1} defined by a*b=a+b+a b for all a ,\ b in Q-{-1} . Then, Show that every element of Q-{-1} is invertible. Also, find the inverse of an arbitrary element.

Let * be a binary operation on Q-{-1} defined by a * b=a+b+a b for all a ,\ b in Q-{-1} . Then, Show that * is both commutative and associative on Q-{-1} . (ii) Find the identity element in Q-{-1}

Consider the binary operation * defined on Q-{1} by the rule a*b=a+b-a b for all a ,\ b in Q-{1} . The identity element in Q-{1} is (a) 0 (b) 1 (c) 1/2 (d) -1