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Find the point on the line (x+2)/3=(y+1\...

Find the point on the line `(x+2)/3=(y+1\ )/2=(z-3\ )/2` at a distance `3\ sqrt(2)\ ` from the point (1,2,3).

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Statement 1: A point on the line (x+2)/3=(y+1)/2=(z-3)/2 at a distance 3sqrt(2) from the point (1,2,3) lies on the lne (x+7)/5=(y+t)/4=(z-2)/1 Statement 2: If d is the distance between the point (-1,-5,-10) and the point of intersectionof the line (x-2)/3=(y+1)/4=(z-2)/12 with the plane x-y+z=5 then d=13

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