Let `v` and `a` be the instantaneous velocity and acceleration of a particle moving in a plane. Then rate of change of speed `(dv)/(dt)` of the particle is equal to

Let v and a represent instantaneous velocity and acceleration of a particle respectively.

At any instant, the velocity and acceleration of a particle moving along a straight line are v and a. The speed of the particle is increasing if

At any instant, the velocity and acceleration of a particle moving along a straight line are v and a. The speed of the particle is increasing if

A particle moves in the x-y plane according to the law x=t^(2) , y = 2t. Find: (a) velocity and acceleration of the particle as a function of time, (b) the speed and rate of change of speed of the particle as a function of time, (c) the distance travelled by the particle as a function of time. (d) the radius of curvature of the particle as a function of time.

Acceleration of particle moving in straight line can be written as a=(dv)/(dt)=v(dv)/(dx) . From the given graph find acceleration at x=20 m .

Acceleration of particle moving in straight line can be written as a=(dv)/(dt)=v(dv)/(dx) . From the given graph find acceleration at x=20 m .

Acceleration of particle moving in straight line can be written as a=(dv)/(dt)=v(dv)/(dx) . From the given graph find acceleration at x=20 m .

If the instantaneous velocity of a particle is zero, will its instantaneous acceleration be necessarily zero?

If "v" is the velocity of a particle moving in a straight line and "a" is acceleration of the particle,then the speed of the particle would be decreasing if