A uniform horizontal rod of length 40 cm and mass 1.2 kg is supported by two identical wires as shown in figure. Where should a mass of 4.8 kg be placed on the rod so that the same tuning fork may excite the wire on left into its fundamental vibrations and that on right into its first overtone ? Take `g=10ms^-2`

A uniform horizontal rod of length 40 cm and mass 1.2 kg is supported by two identical wires as shown in figure. Where should a mass of 4.8 kg be placed on the ord form left end (in cm ) so that the same tuning fork may excite the wire on left into its fundament vibrations and that on right into its first overtone? Take g = 10 m//s^(2) .

A metal rod of length 50cm having mass 2kg is supported on two edges placed 10cm from each end. A 3kg load is suspended at 20cm from one end. Find the reactions at the edges (take g=10m//s^(2) )

A metal rod of length 50cm having mass 2kg is supported on two edges placed 10cm from each end. A 3kg load is suspended at 20cm from one end. Find the reactions at the edges (take g=10m//s^(2) )

A metal rod of length 50cm having mass 2kg is supported on two edges placed 10cm from each end. A 3kg load is suspended at 20cm from one end. Find the reactions at the edges (take g=10m//s^(2) )

A straight horizontal conducting rod of length 0*60m and mass of 60g is suspended by two vertical wires at its ends. A current of 5*0A is set up in the rod through the wire. (a) What magnetic field should be set up normal to the conductor in order that the tension in the wire is zero? (b) What will be total tension in the wires if the direction of current is reversed, keeping the magnetic field same as before (Ignore mass of the wire), g=10ms^-2 .