A line with direction cosines proportional to `1,-5, a n d-2` meets lines `x=y+5=z+1a n dx+5=3y=2zdot` The coordinates of each of the points of the intersection are given by a. `(2,-3,1)` b. `(1,2,3)` c. `(0,5//3,5//2)` d. `(3,-2,2)`

A line with direction cosines proportional to 2,1,2 meet each of the lines x=y+a=z and x+a=2y=2z . The coordinastes of each of the points of intersection are given by (A) (3a,2a,3a),(a,a,2a) (B) (3a,2a,3a),(a,a,a0 (C) (3a,3a,3a),(a,a,a) (D) 92a,3a,3a),(2a,a,a0

A line with cosines proportional to 2,7-5 drawn to intersect the lines (x-5)/(3)=(y-7)/(-1)=(z+2)/(1);(x+3)/(-3)=(y-3)/(2)=(z-6)/(4) .Find the co- ordinates of the points of intersection and the length intercepted on it.

The image of the point (1, 3, 4) in the plane 2x-y+z+3=0 is (3,\ 5,\ 2) b. (-3,5,\ 2) c. (3,\ 5,\ -2) d. (3,\ -5,\ 2)

The point of intersection of the two lines given by 2x^(2)-5xy+2y^(2)-3x+3y+1=0 is

Show that the two lines (x-1)/2=(y-2)/3=(z-3)/4 and (x-4)/5=(y-1)/2=z intersect. Find also the point of intersection of these lines.

The direction cosines of a line parallel to the line (x+1)/(2)=(y)/(-3)=(z-5)/(6) are