A spherical balloon is being inflated so that its volume increase uniformly at the rate of `40cm^3/min`. How much the radius will increases during the next 1/2 minute ?

A spherical balloon is being inflated so that its volume increase uniformly at the rate of 40(cm)^3/min . How much the radius will increases during the next 1/2 minute,if initial radius is 8cm. ?

A spherical balloon is being inflated so that its volume increase uniformly at the rate of 40c(m^(3))/(min). How much the radius will increases during the next 1/2 minute ?

A spherical balloon is being inflated so that itsvolume increases uniformly at the rate of 40cm3/min .How fast is its surface area increasing when the radius is 8cm? Find how much approximately the radius will increase during the next (1)/(2) minute.

A spherical balloon is being inflated so that its volume increase uniformaly at the rate of 40 cm^(3)//"minute" . The rate of increase in its surface area when the radius is 8 cm, is

A spherical balloon is being inflated so that its volume increase uniformaly at the rate of 40 cm^(3)//"minute" . The rate of increase in its surface area when the radius is 8 cm, is

A spherical balloon is being inflated so that its volume increase uniformaly at the rate of 40 cm^(3)//"minute" . The rate of increase in its surface area when the radius is 8 cm, is

The spherical ballon is being inflated so that its volume increases uniformly at the rate of 40 cubic cm per minute. The rate of increase in the surface as when the radius is 8 cm is

A shperical balloon is being inflated so that its volume increases uniformly at the of 40 cm^(3) / min. How fast is its surface area increasing, when the radius is 8 cm? Find approximately how much the radius is 8 cm ? Find approximately how much the radius will increase during the next (1)/(2) minute.

A spherical balloon grows to twice its radius when inflated. How has its volume increased ?

A balloon is filled in such a way that its volume increases at the rate of 40 cm^(3) /min. when radius is 8 cm, the rate of increases in the surface area is ……………. cm^(2) /min.