Consider a two slit interference arrangements (figure) such that the distance of the screen from the slits is half the distance between the slits. Obtain the value of D in terms of `lambda` such that the first minima on the screen falls at a distance D from the centre O.

Consider a two slit interference arrangements (Fig. EP 10.18) such that the distance of the screen from the slits is half the distance between the slits. Obtain the value of D in terms of lambda such that the first minima on the screen falls at a distance D from the center O.

Conisder a two slit interference arrangement as shown in Fig.6.07. Here,CO=D and S_1C=SC_2=D i.e. the distance of the screen from the slits is half the distance between the slits.Obtain the value of D in terms of lamda ,such that the first minima on the screen falls at a distance D from the cetreO.

In a YDSE arrangement, the distance of screen from the slits is half the distance between the slits. If 'lambda' is the wavelength of then the value of D such that first minima on the screen falls at a distance D from then centre 'O' is

Consider two slit interference arrangements as shown in figure . The distance of screen from the slits is half the distance between the slits. Then the value of 'D' if fisrt minima on screen falls at a distance D from the centre 'C' ( lambda is the wavelength of the source).

In a special arrangement of Young's double - slits d is twice the distance between the screen and the slits D, i.e. d = 2D. For the setup, the value of D such that the first minima on the screen fall at a distance D from the centre O is found to be (lambda)/(N) , where lambda is the wavelength of light used. What is the value of N ? ["Take "sqrt5=2.24]

In a special arrangement of Young's double - slits d is twice the distance between the screen and the slits D, i.e. d = 2D. For the setup, the value of D such that the first minima on the screen fall at a distance D from the centre O is found to be (lambda)/(N) , where lambda is the wavelength of light used. What is the value of N ? ["Take "sqrt5=2.24]

In young's double slit experiment, if the distance between the slits is halved and the distance between the slits and the screen is doubled, the fringe width becomes