O(0,0), A(1,2), B(3,4) are the vertices of `DeltaOAB`. The joint equation of the altitude and median drawn from O is

A(-3,0),B(1,3),C(2,-1) are the vertices of triangleABC . Then the equation of the altitude from A to BC is :

If O(0, 0), A(3, 4), B(4, 3) are the vertices of a triangle then the length of the altitude from O is

A(-3, 0), B(10, -2) and C(12, 3) are the vertices of triangleABC . Find the equation of the altitude through A and B.

Let A(1, 2, 3), B(0, 0, 1), C(-1, 1, 1) are the vertices of a DeltaABC .The equation of median through C to side AB is

Let A(1, 2, 3), B(0, 0, 1), C(-1, 1, 1) are the vertices of a DeltaABC .The equation of median through C to side AB is

O (0, 0), A (3, 5) and B (-5, -3) are the vertices of triangle OAB. Find : the equation of median of triangle OAB through vertex O.

If A(1, 4), B(2, -3) and C (-1, -2) are the vertices of a DeltaABC . Find (i) the equation of the median through A (ii) the equation of the altitude through A. (iii) the right bisector of the side BC .