The rate of diffusion of methane is twice that of X. The molecular mass of X is

The rate of diffusion of methane is twice that of the following gas under the same conditions

The rate of diffusion of a gas X is sqrt(2) times that of Y. If the molecular mass X is 16, what is the molecular mass of gas y?

The rate of diffusion of a gas X is sqrt(2) times that of Y. If the molecular masss X is 16, what is the molecular mass of gas y?

What is the ratio of rate of diffusion of gas A and B . The molecular mass of A is 11 and molecular mass of B is 44 .

What is the ratio of rate of diffusion of gas A and B . The molecular mass of A is 11 and molecular mass of B is 44 .

The rate of diffusion of methane at a given temperature is twice that of a gas X. The molecular weight of X is :

Molecular mass of methane is

Rate of diffusion of gas A is (1)/(2) that of gas 'B'. If molecular mass of gas A is 16 than calculate molecular mass of gas 'B'.