When a dielectric material is introduced between the plates of a charged condenser, after disconnected the battery the electric field between the plates

When a dielectric material is introduced between the plates of a charged condenser the electric field between the plates

A parallel plate capacitor is connected to a battery of emf V volts. Now a slab of dielectric constant k=2 is inserted between the plates of capacitor without disconnecting the battery. The electric field between the plates of capacitor after inserting the slab is E= (PV)/(2d) . Find the value of P.

A parallel plate capacitor is connecyed to a battery of emf V volts as shown. Now a slab of dielectric constant k=2 is inserted between the plates of capacitor without disconnecting the battery. The electric field between the plates of capacitor after inserting the slab is E= (PV)/(2d) . Find the value of P.

When a dielectric slab of thickness 6 cm is introduced between the plates of parallel plate condenser, it is found that the distance between the plates has to be increased by 4 cm to restore to capacity original value. The dielectric constant of the slab is

When a slab of dielectric material is introduced between the parallel plants of a capcitor which remains connected to a battery, then charges on plates relative to earlier charge

When a dielectric slab of thickness 4 cm is introduced between the plates of parallel plate condenser, it is found the distance between the plates has to be increased by 3 cm to restore to capacity to original value. The dielectric constant of the slab is.